The perimeter of a rectangle is at least 100 inches, and the width must be less than double the length. The length must be over 15 inches long. Which of the following inequalities correctly describes the perimeter?(1 point)

Question

Responses

2L+15W≥100
2
𝐿
+
15
𝑊
≥
100
2 upper L plus 15 upper W greater-than-or-equal-to 100

2L+2W≥100
2
𝐿
+
2
𝑊
≥
100
2 upper L plus 2 upper W greater-than-or-equal-to 100

L+W≥100
𝐿
+
𝑊
≥
100
upper L plus upper W greater-than-or-equal-to 100

2L+2W≤100

Answer 1

The perimeter \( P \) of a rectangle is calculated using the formula:

\[ P = 2L + 2W \]

According to the problem, we know the following:

1. The perimeter must be at least 100 inches: \[ 2L + 2W \geq 100 \]

2. The width \( W \) must be less than double the length \( L \): \[ W < 2L \]

3. The length \( L \) must be over 15 inches: \[ L > 15 \]

Based on the information about the perimeter, the correct inequality that represents the condition of the perimeter being at least 100 inches is:

\[ 2L + 2W \geq 100 \]

Therefore, the correct response is:

2L + 2W ≥ 100