A = LW 120 = LW or 120/l = W
P = 2L + 2W
46 = 2L + 2(120/L)
multiply through by L
46L = 2L^2 + 240
2L^2 - 46L + 240 = 0
2(L^2 - 23L + 120) = 0
Factor and set each part equal to zero. Omit the negative value for x.
Once you have the Length substitute into the original equation to find Width.
The perimeter of a rectangle is 46 inches, and the area is 120 square inches. Find the length and width of the rectangle.
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