the perimeter of a rectangle is 40 feet and its area is 96 square feet. find the length and width?

1 answer

2L + 2W = 40

Divide both sides of first equation by 2.

L + W = 20, Then W = 20 - L

L * W = 96

Substitute 20-L for W in second equation and solve for L. Insert that value into the first equation and solve for W. Check by inserting both values into the second equation.