Asked by danica
the perimeter of a rectangle is 160m and its area is 1200m^2 find its dimensions
Answers
Answered by
Ms. Sue
I'll get you started.
√ 1200 = 34.64
√ 1200 = 34.64
Answered by
danica
then what i seriously have no clue what im doing
Answered by
Ms. Sue
With a little trial and error, I found that the dimensions must be 20 by 60
Answered by
Reiny
2w + 2l = 160
w+l = 80
l= 80-w
wl = 1200
w(80-w) = 1200
80w - w^2 - 1200=0
w^2 - 80w + 1200 = 0
(w-20)(w - 60) = 0
w = 20 or w = 60
if w = 20, then l = 80-20 = 60
and if w - 60 , then l = 80-60 = 20
So the rectangle is 20 by 60 as Ms Sue found by trial-and-error
w+l = 80
l= 80-w
wl = 1200
w(80-w) = 1200
80w - w^2 - 1200=0
w^2 - 80w + 1200 = 0
(w-20)(w - 60) = 0
w = 20 or w = 60
if w = 20, then l = 80-20 = 60
and if w - 60 , then l = 80-60 = 20
So the rectangle is 20 by 60 as Ms Sue found by trial-and-error
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