2l + 2w=106
2(w+7)+2w=106
you take it from here.
The perimeter of a rectangle is 106 inches,the length exceeds the width by 7 inches, find the length and the width
2 answers
the answers are...
w=23
l=30
use this formula...
2L+2W=106
2(w+7)+2W=106
^Factor the 2 with (W+7)
then solve for W.
thats the first part.
then use the same formula...
2L+2W=106
plug in your W
then solve for L
w=23
l=30
use this formula...
2L+2W=106
2(w+7)+2W=106
^Factor the 2 with (W+7)
then solve for W.
thats the first part.
then use the same formula...
2L+2W=106
plug in your W
then solve for L