P(t) = 100(1-e^-0.12*3)
P(3) = 100(1-0.6977) = 30.23% Fails.
100% - 30.23% = 69.7% Usable.
The percentage of a certain brand of computer chips that will fail after t years of use is estimated to be
P(t) = 100(1 − e−0.12t ).
What percentage of this brand of computer chips are expected to be usable after 3 years? (Round your answer to one decimal place.)
1 answer