To determine how many rounds of evaluation it takes for only 4 applications to remain from an initial 1,024 applications, we can use the equation:
\[ 1024 = 4 \times (1/2)^x \]
We can rearrange this into a more standard form:
\[ 1024 = 4 \cdot \left(\frac{1}{2}\right)^x \]
This means we can rewrite it as:
\[ 1024 = 4 \cdot \left(2^{-1}\right)^x \]
Since \( (2^{-1})^x = 2^{-x} \), it follows that:
\[ 1024 = 4 \cdot 2^{-x} \]
Now, expressing everything in terms of powers of 2:
- We know that \( 1024 = 2^{10} \)
- And \( 4 = 2^2 \)
Thus, the equation becomes:
\[ 2^{10} = 2^2 \cdot 2^{-x} \]
Which simplifies to:
\[ 2^{10} = 2^{2 - x} \]
Since the bases are the same, we can equate the exponents:
\[ 10 = 2 - x \]
Solving for \(x\):
\[ x = 2 - 10 = -8 \]
However, it seems like we've gone slightly off. We instead want \(2^x\) instead of \(-x\). So ultimately we realize that calculation of x
should yield rounds until 4 is reached:
If starting from 1024, we can divide it successively until 4 remains.
- After 1 round: 1024 / 2 = 512
- After 2 rounds: 512 / 2 = 256
- After 3 rounds: 256 / 2 = 128
- After 4 rounds: 128 / 2 = 64
- After 5 rounds: 64 / 2 = 32
- After 6 rounds: 32 / 2 = 16
- After 7 rounds: 16 / 2 = 8
- After 8 rounds: 8 / 2 = 4
Therefore, your answer should be
1024 = 4(1/2)^8
So the appropriate values to fill in the blanks are:
=(1/2)^8
Where the first blank is 1024
, the second blank is 4
, and x
is 8
.