s=t^3-6t^2+9t+4
v = 3t^2 - 12t + 9 = 3(t-1)(t-3)
a = 6t-12 = 6(t-2)
s is increasing when v > 0
v is increasing when a > 0
The path of a particle moving in a straight line is given by s=t^3-6t^2+9t+4.
a. Find s and a when v=0.
b. Find s and v when a=0.
c. When is s increasing?
d. When is v increasing?
3 answers
23
25