weight at bottom: mg+mv^2/r
but that is equal to 1.50 mg
solve for v.
The passengers in a roller coaster car feel 50% heavier than their true weight as the car goes through a dip with a 20 m radius of curvature.
What is the car's speed at the bottom of the dip?
7 answers
Force of gravity at the bottom=mg+mv^2/r, set that equal to 1.5(mg). All the m's divide out, leaving 1.5(g)=g+v^2/r. Plug in the numbers now.
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