The particular solution of the differential equation dy/dt=y/4 for which y(0) = 20 is
y = 20e^-0.25t
y = 19 + e^0.25t
y = 20 e^0.25t
y = 20^e4t
1 answer
Looks like (c) to me
y = 20e^-0.25t
y = 19 + e^0.25t
y = 20 e^0.25t
y = 20^e4t
1 answer