Are you allowed to look up information OR do you have the normal vapor pressure of water at 25 degrees C in the problem?
Po H2O @ 25 degres C = 23.8 mm I believe but check me out on that. If it's listed in the problem use that value.
Then delta P = X(solute)*P(solvent)
delta P then is 23.8-19.2 = X(solute)*23.8 and you solve for X(solute).
The partial pressure of water above a solution of water and a nonvolatile solute at 25oC is 19.2 mm Hg. What is the mole fraction of the solute
please help....I really don't know how I am supposed to solve this question.
I know that Partial pressure of the solvent above a soln = (mole fraction of solvent)(Vapor pressure above the pure solvent)
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