The partial pressure of fluorine gas (F2) in a mixture of gases where the total pressure is 1.00 atm is 300. torr. What percent of the mixture is made of fluorine gas
2 answers
I worked this problem below.
the ratio of the presure is directly proportional to the mole ratio.
molesF2=.3 total moles
total moles=RT/PV
percent of Moles F2 is 30 percent.
percent by mass depends on what the mass of the other gases is.
molesF2=.3 total moles
total moles=RT/PV
percent of Moles F2 is 30 percent.
percent by mass depends on what the mass of the other gases is.
1 answer