To find the area of the parallelogram OPQR, we can find the area of one of the triangles (OPR) and then multiply it by 2 since the parallelogram is bisected by PR.
First, let's find the area of triangle OPR:
- The base of triangle OPR is 4 units (from O to R).
- The height of triangle OPR is 3 units (from O to the line PR).
- The area of triangle OPR is (1/2) * base * height = (1/2) * 4 * 3 = 6 square units.
Now, since the parallelogram is bisected by PR, both triangles OPR and QRP will have the same area. Therefore, the total area of parallelogram OPQR is:
2 * (area of triangle OPR) = 2 * 6 = 12 square units
Therefore, the area of parallelogram OPQR is 12 square units, and the area of triangle OPR is 6 square units.
The parallelogram on the grid is bisected by line segment PR. What is the AREA of Parallelogram OPQR and of Triangle OPR? (2 points) Responses
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