the oxidation number of Mo in Na2MoO4 is what?

2 answers

Compounds must add up to zero.
Na is +1; 2*1 = +2
O is -2; 4*-2 = -8
So Mo must be ...... for Na2MoO4 to be zero.
Na2MoO4= 0Γ—2+x+4(-2)=0
=0+x+(-6)=0
= x-6=0
π˜Όπ™£π™¨π™¬π™šπ™§ =x=6
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