Compounds must add up to zero.
Na is +1; 2*1 = +2
O is -2; 4*-2 = -8
So Mo must be ...... for Na2MoO4 to be zero.
the oxidation number of Mo in Na2MoO4 is what?
2 answers
Na2MoO4= 0Γ2+x+4(-2)=0
=0+x+(-6)=0
= x-6=0
πΌπ£π¨π¬ππ§ =x=6
ππππ£ π¬π πππ£π π€πππππ©ππ€π£ π¨π©ππ©π π€π ππ€
=0+x+(-6)=0
= x-6=0
πΌπ£π¨π¬ππ§ =x=6
ππππ£ π¬π πππ£π π€πππππ©ππ€π£ π¨π©ππ©π π€π ππ€