The other tooth of an airplane is decreasing at a rate of 45 ft./s. What is the change in altitude of the airplane over a period of 28 seconds

A. 73 feet
B. -1260 feet
C. 1260 feet
D. -73 feet

1 answer

To solve this problem, we need to find the change in altitude of the airplane over a period of 28 seconds.

We are given that the other tooth (presumably engine) of the airplane is decreasing at a rate of 45 ft/s. This means that the altitude of the airplane is decreasing at a rate of 45 ft/s.

The change in altitude is calculated by multiplying the rate of change (45 ft/s) by the time (28 seconds):

Change in altitude = rate of change x time
Change in altitude = 45 ft/s x 28 s
Change in altitude = 1260 feet

Therefore, the change in altitude of the airplane over a period of 28 seconds is 1260 feet.

The answer is C. 1260 feet.