Asked by sierra
The operating cost, C, in dollars per hour, for an airplane cruising at a height of h metres and an air speed of 200km/h is given by:
C = 4000 + h/15 + 15000000/h
for the domain 1000 ≤ h ≤ 20000.
Determine the height at which the operating cost is at a minimum, and find the operating cost per hour at this height.
So far this is what I've tried:
C' = 4000 + 1/15 -15000000/h^2
I have no clue what to do next lol plz help
C = 4000 + h/15 + 15000000/h
for the domain 1000 ≤ h ≤ 20000.
Determine the height at which the operating cost is at a minimum, and find the operating cost per hour at this height.
So far this is what I've tried:
C' = 4000 + 1/15 -15000000/h^2
I have no clue what to do next lol plz help
Answers
Answered by
MathMate
1. find derivative with respect to h:
C'(h) = 1/15-15000000/h²
2. equate C'(h) to zero and solve for h.
2. 1/15-15000000/h² = 0
h²=225000000
h=15000
3. verify that it is a minimum (not maximum) by taking second derivative, and see that C"(15000)>0.
(if C"(15000)<0, then it is a maximum).
C"(h)=30000000/h³
C"(15000)=1/112500 > 0
so h=15000 is a minimum.
C'(h) = 1/15-15000000/h²
2. equate C'(h) to zero and solve for h.
2. 1/15-15000000/h² = 0
h²=225000000
h=15000
3. verify that it is a minimum (not maximum) by taking second derivative, and see that C"(15000)>0.
(if C"(15000)<0, then it is a maximum).
C"(h)=30000000/h³
C"(15000)=1/112500 > 0
so h=15000 is a minimum.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.