The numerator of a fractionis 5 less than twice the denominator. If the numerator is decreased by 1 and the denominator is increased by 3, the value of the new fraction is 5/4. Find the original fraction.

Answer 1

old denominator --- D
old numerator --- 2D-5

new denomintor D-1
new denom. 2D-5 + 3

so (D-1)/(2D-2) = 5/4

solve

Answer 2

I seem to be making some silly copying errors tonight

change to :

new denomintor D+3
new numerator 2D-5 - 1

so (2D-6)/(D+3) = 5/4

solve

Answer 3

This is my work:

D-1 5
-----= -- Cross multiply you get:
2D-2 4 10D-10=4D-4
-4D -4D
6D-10=-4
+10+10
6D=6
-----
6 6
D=1?

Answer 4

Oh now I get it. in the last step
3D=39
-----
3 3

so D=13
tysm!
your a genius.

Answer 5

THE DENOMINATOR IS 4 MORE THAN ITS NUMERATOR.IT IS DECREASED FROM NUMERATOR AND 2 IS ADDED TO THE DENOMINATOR,THE RESULTING FRACTION IS 3/4.FIND THE ORIGINAL FRACTION.