The numbers i�ã5 and -i�ã5 are solutions to which equation?
a. x^2+�ã5=0
b. x^2+5=0
d. x^2-5=0
3 answers
thank you do you know how to do it though?
of course. I got the answer
you say √5i and -√5i are the solutions, so
(x-√5i)(x+√5i) = 0
x^2 - (√5i)^2 = 0
x^2 - 5i^2 = 0
but i^2 = -1, so
x^2 + 5 = 0
you say √5i and -√5i are the solutions, so
(x-√5i)(x+√5i) = 0
x^2 - (√5i)^2 = 0
x^2 - 5i^2 = 0
but i^2 = -1, so
x^2 + 5 = 0
omg thank you soooo much (: