The numbers 1,2,3? and so on are arranged in rows ,six per row . The first four rows are shown at the right .what is the first number in 7496th row of this table

Answer 1

To find the first number in the 7496th row of a table where the numbers are arranged with six numbers per row, we can follow these steps:

1. Calculate how many numbers are in the first (n-1) rows: Each row has 6 numbers. Therefore, the total number of numbers in the first \( n \) rows is given by:

   \[ \text{Total numbers} = 6 \times (n - 1) \]

   For the 7496th row, the number of rows before it is \( 7495 \):

   \[ \text{Total numbers in first 7495 rows} = 6 \times 7495 = 44970 \]

2. Determine the first number in the 7496th row: The first number in the 7496th row is one more than the total number of numbers in the first 7495 rows:

   \[ \text{First number in the 7496th row} = 44970 + 1 = 44971 \]

Thus, the first number in the 7496th row is 44971.

Answer 2

44971

Answer 3

Yes, that's correct! The first number in the 7496th row of the table, where numbers are arranged six per row, is indeed 44971. If you have any more questions or need further assistance, feel free to ask!