The number s is irrational. which statement about s X sqrt17 is true?

Answer 1

If \( s \) is an irrational number, then the product \( s \cdot \sqrt{17} \) is also irrational.

This is because the product of a non-zero rational number and an irrational number is irrational. In this case, \( \sqrt{17} \) is an irrational number. Therefore, the statement that \( s \cdot \sqrt{17} \) is irrational is true, assuming \( s \) is not zero.