#14. well, e^0 = 1, so N(0) = 10000/1250
#15. Just plug in 1 or 5 for t and crank it out.
#16 just solve for t in
10,000/(5 + 1245e-.97t) = 1000
5 + 1245e-.97t = 10
1245e^-.97t = 5
e^-.97t = 5/1245
-.97t = ln(5/1245) = -5.517
t = 5.68 days
The number of people in a town of 10,000 who have heard a rumor started by a small group of people is given by the following function:
N(t) = 10,000/(5 + 1245e-.97t)
14. How many people were in the group that started the rumor?
15. How many people have heard the rumor after 1 day? After 5 days?
16. How long before 1000 of the people in the town have heard the rumor?
1 answer