the number of moles of H2O2 required to completely react with 400ml of 0.5N KMnO4 in acidic medium are
3 answers
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According to the law of gram equivalents, the reacting portions of the reactants always have equal gram equivalents (Geq). Therefore,
Geq of KMnO4 = Normality × Volume
= 0.5 × 400/1000
= 0.2
Geq of H2O2 = No. of moles (x) × n factor
= 2x
∴ 2x = 0.2
x = 0.1
Geq of KMnO4 = Normality × Volume
= 0.5 × 400/1000
= 0.2
Geq of H2O2 = No. of moles (x) × n factor
= 2x
∴ 2x = 0.2
x = 0.1
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