The number of hours a group of contestants spends preparing for a quiz show is listed below. What is the frequency table that represents that data?

Question

8 12 25 32 45 50 62 73 80 99 4 18 9 39 36 67 33
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Option 1.
Hours. Frequency
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0-9. 3
10-19. 2
20-29. 1
30-39. 4
40-49. 1
50-59. 1
60-69. 2
70-79. 1
80-89. 1
90-99. 1
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Option 2.
Hours. Frequency
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0-9. 2
10-19. 3
20-29. 1
30-39. 3
40-49. 2
50-59. 1
60-69. 2
70-79. 1
80-89. 1
90-99. 1
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Option 3.
Hours. Frequency
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0-9. 4
10-19. 1
20-29. 0
30-39. 4
40-49. 2
50-59. 1
60-69. 2
70-79. 1
80-89. 1
90-99. 1
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Option 4.
Hours. Frequency
----------------------------------------
0-9. 3
10-19. 2
20-29. 1
30-39. 4
40-49. 1
50-59. 1
60-69. 2
70-79. 1
80-89. 1
90-99. 2
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My answer is option #4

Answer 1

8 4 and 9 is 3 from 0 to 9
so has to be 1 or 4

option 1 has 1 from 90 to 99
but there are 2 in option 4

so I think option 1

Answer 2

So was it option 1? Or option 4

Answer 3

22. What are the minimum, first quartile, median, third quartile, and maximum of the data set?
18, 20, 11, 10, 8, 6, 12, 4 (1 point)
minimum 4; first quartile 7; median 10.5; third quartile 17.5; maximum 20
minimum 4; first quartile 5.5; median 12.75; third quartile 15; maximum 20
minimum 4; first quartile 8.75; median 12.75; third quartile 17.5; maximum 20
minimum 4; first quartile 7; median 10.5; third quartile 15; maximum 20
23. Simplify –(3ab2)–3 (1 point)
(Image: 1 over 9a3b6)
(Image: –1 over 27a3b6)
(Image: –1 over 3a3b5)
27a3b6

Answer 4

23. Simplify –(3ab2)–3:

-(3ab^2)^-3

= -1/(3ab^2)^3

= -1/(27a^3b^6)

The answer is (Image: –1 over 27a3b6).