To find the corresponding time for each number of cells using the equation \( N(t) = 80(3^t) \), we can substitute each time value into the equation and see if it matches one of the given cell counts.
Let's calculate the number of cells for \( t = 5, 6, \) and \( 7 \):
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For \( t = 5 \): \[ N(5) = 80(3^5) = 80 \cdot 243 = 19440 \]
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For \( t = 6 \): \[ N(6) = 80(3^6) = 80 \cdot 729 = 58320 \]
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For \( t = 7 \): \[ N(7) = 80(3^7) = 80 \cdot 2187 = 174960 \]
Now, we can match the numbers of cells to the corresponding times:
- 174960 - 7 hours
- 58320 - 6 hours
- 19440 - 5 hours (not in your list, but here for completeness)
So, the final matching is:
- 174960 - 7 hours
- 58320 - 6 hours