The number of cases of flu in building 1 is representative of the following where x is number of days since the first case of the flu was reported f(x) = 14.25x^2 + 3

The number of cases of the flu in building 2 is represented by the gray where x is number of days since the first day it was reported
The graph passes through the points (0,3),(1,12),(2,48),(3,192)
Complete the table
x 0 1 2 3
Building 1
Building 2

1 answer

To complete the table for both Building 1 and Building 2, we can calculate the number of flu cases in Building 1 using the function provided, \( f(x) = 14.25x^2 + 3 \), and we can list the values for Building 2 based on the points given: (0,3), (1,12), (2,48), and (3,192).

Calculations for Building 1:

  1. For \( x = 0 \): \[ f(0) = 14.25(0)^2 + 3 = 3 \]

  2. For \( x = 1 \): \[ f(1) = 14.25(1)^2 + 3 = 14.25 + 3 = 17.25 \]

  3. For \( x = 2 \): \[ f(2) = 14.25(2)^2 + 3 = 14.25(4) + 3 = 57 + 3 = 60 \]

  4. For \( x = 3 \): \[ f(3) = 14.25(3)^2 + 3 = 14.25(9) + 3 = 128.25 + 3 = 131.25 \]

Assigning values to Building 2 based on provided points:

  • The values for Building 2 corresponding to \( x = 0, 1, 2, 3 \) are:
    • For \( x = 0 \): 3
    • For \( x = 1 \): 12
    • For \( x = 2 \): 48
    • For \( x = 3 \): 192

Complete the table:

| x | Building 1 | Building 2 | |----|-------------|-------------| | 0 | 3 | 3 | | 1 | 17.25 | 12 | | 2 | 60 | 48 | | 3 | 131.25 | 192 |

This completes the table with the calculated values for Building 1 and the specified values for Building 2.

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