The number of calories in an order of population of abc reastorant is 740 calories on average and 20 standard devation. if you take a sample of 36 order.what is the probability of getting at least 745 calories?

Answer 1

To solve this problem, we need to use the formula for the z-score:

z = (x - μ) / (σ / sqrt(n))

Where:

x = 745 calories (since we want to find the probability of getting at least 745 calories)
μ = 740 calories (the population mean)
σ = 20 calories (the population standard deviation)
n = 36 (the sample size)

Plugging in the values, we get:

z = (745 - 740) / (20 / sqrt(36))
z = 1.5

Now, we need to find the probability of getting a z-score of 1.5 or more. We can use a standard normal distribution table or calculator to find this probability. The probability of getting a z-score of 1.5 or more is 0.0668.

Therefore, the probability of getting at least 745 calories in a sample of 36 orders is 0.0668 or approximately 6.68%.