The number of bugs doubles every 4 days. If the bug population starts with 6 bugs, then the equation A(t)=6(2)^0.25t

can represent the number of bugs. Find the value for A(8)
.(1 point)
The number of bugs after 8 days is
___.

1 answer

To find the value of \( A(8) \), we can substitute \( t = 8 \) into the equation:

\[ A(t) = 6(2)^{0.25t} \]

Substituting \( t = 8 \):

\[ A(8) = 6(2)^{0.25 \times 8} \]

Calculating \( 0.25 \times 8 \):

\[ 0.25 \times 8 = 2 \]

So we have:

\[ A(8) = 6(2)^2 \]

Now, calculate \( (2)^2 \):

\[ (2)^2 = 4 \]

Now multiply by 6:

\[ A(8) = 6 \cdot 4 = 24 \]

Thus, the number of bugs after 8 days is \( \boxed{24} \).