The number of bugs doubles every 4 days. If the bug population starts with 6 bugs, then the equation A(t)=6(2)0.25t

can represent the number of bugs. Find the value for A(8)
.(1 point)
The number of bugs after 8 days is
.
Remaining Attempts : 3

1 answer

To find the number of bugs after 8 days using the equation \( A(t) = 6(2)^{0.25t} \), we first substitute \( t = 8 \):

\[ A(8) = 6(2)^{0.25 \cdot 8} \]

Calculating \( 0.25 \cdot 8 \):

\[ 0.25 \cdot 8 = 2 \]

Now we can substitute this back into the equation:

\[ A(8) = 6(2)^2 \]

Calculating \( (2)^2 \):

\[ (2)^2 = 4 \]

Now multiply:

\[ A(8) = 6 \cdot 4 = 24 \]

Therefore, the number of bugs after 8 days is \( 24 \).