the number of atoms of oxygen present in 11.2 l of ozone at ntp are

Answer 1

To determine the number of atoms of oxygen present in 11.2 L of ozone at NTP (Normal Temperature and Pressure), we need to calculate the number of moles of ozone and then multiply it by the Avogadro's number to get the number of atoms.

The molar volume of a gas at NTP is 22.4 L/mol.

First, let's calculate the number of moles of ozone:

11.2 L of ozone / 22.4 L/mol = 0.5 mol of ozone

Ozone (O3) has three oxygen atoms.

Number of atoms of oxygen in 0.5 mol of ozone = 0.5 mol x 3 atoms/mol = 1.5 mol

Now, we will multiply the number of moles of oxygen by Avogadro's number (6.022 x 10^23 atoms/mol) to get the number of atoms:

1.5 mol x 6.022 x 10^23 atoms/mol = 9.033 x 10^23 atoms of oxygen

Therefore, there are approximately 9.033 x 10^23 atoms of oxygen present in 11.2 L of ozone at NTP.