Asked by Jeremy

The nuclide 96Nb decays by a first-order process with a rate constant of 2.96 × 10-2 h-1. How long will it take for 85% of the initial amount of 96Nb to be consumed?

I believe it is 5.07 hrs...
Answered by DrBob222
nope.
ln(No/N) = kt
No = 100 (You can choose any convenient number)
N = 15 (85% has been consumed)
k = 0.0296
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