The normality of NaOH obtained was 0.0172, 0.0187, 0.0185, 0.189, and 0.0183 N. The theoretical normality of NaOH was 0.02 N. Please calculate:
1) Standard deviation based on the true mean:
2) Standard deviation based on the experimental mean: SD
3) Coefficient of variation (CV)
4) Confidence Interval of 95% certainty
2 answers
Y'all take forever to answer
1) Subtract each of the scores from the mean and square each difference. Find the sum of these squares. Divide that by the number of scores to get variance.
Standard deviation = square root of variance
2) Find the mean first = sum of scores/number of scores
Subtract each of the scores from the mean and square each difference. Find the sum of these squares. Divide that by the number of scores to get variance.
Standard deviation = square root of variance
3) https://www.google.com/search?client=safari&rls=en&q=Coefficient+of+variation&ie=UTF-8&oe=UTF-8
4) 95% = mean ± 2 SD
I'll let you do the calculations.
We balance our postings with other factors in our lives.
Standard deviation = square root of variance
2) Find the mean first = sum of scores/number of scores
Subtract each of the scores from the mean and square each difference. Find the sum of these squares. Divide that by the number of scores to get variance.
Standard deviation = square root of variance
3) https://www.google.com/search?client=safari&rls=en&q=Coefficient+of+variation&ie=UTF-8&oe=UTF-8
4) 95% = mean ± 2 SD
I'll let you do the calculations.
We balance our postings with other factors in our lives.
2 answers