The normal boiling point of benzene is 80 degree C and its heat of vaporizations is 30.8 kj/mol. What is its boiling point at the top of Pikes Peak where P=260 mmHg?
4 answers
Use the Clausius-Clapeyron equation.
Thanks Dr. B, I know to use that equation but the math is the part that I'm stuck on.
ln(P1/P2) = deltaHvap/R(1/T2 - 1/T1)
ln(760/260) = 30,800/8.314(1/T2 - 1/353)
Solve for T2. You can check you numbers with this. If those numbers are ok you can post your work and I'll try to find the error.
ln(760/260) = 30,800/8.314(1/T2 - 1/353)
Solve for T2. You can check you numbers with this. If those numbers are ok you can post your work and I'll try to find the error.
Yeah that's the same setup I have but I'm not sure once I divide 30800/8.314 if I take that number and multiply by the other side of the equation or if I'm supposed to FOIL it out with the temps in parenthesis? Thanks!
1 answer