the normal acceleration of a particle on the rim of a pulley 10 ft in diameter is constant @ 8000 ft/s^2. determine the speed of the pulley in rpm

Answer 1

r = 5 ft
a = v^2/r = v^2/5 = 8000
v^2 = 40,000
v = 200 ft/s

v = w r = 2 pi f r
200 = 2 pi f (5)
2 pi f = 40 radians/sec

40 rad/s (1 rev/2 pi rad)(60 s/min)
= 392 revs/min