Asked by fatz
the normal acceleration of a particle on the rim of a pulley 10 ft in diameter is constant @ 8000 ft/s^2. determine the speed of the pulley in rpm
Answers
Answered by
Damon
r = 5 ft
a = v^2/r = v^2/5 = 8000
v^2 = 40,000
v = 200 ft/s
v = w r = 2 pi f r
200 = 2 pi f (5)
2 pi f = 40 radians/sec
40 rad/s (1 rev/2 pi rad)(60 s/min)
= 392 revs/min
a = v^2/r = v^2/5 = 8000
v^2 = 40,000
v = 200 ft/s
v = w r = 2 pi f r
200 = 2 pi f (5)
2 pi f = 40 radians/sec
40 rad/s (1 rev/2 pi rad)(60 s/min)
= 392 revs/min
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