(1/2) I w^2 = 1822.5 J
w = 110 rad/s
Solve for I, the moment of inertia
The net work done in accelerating a propeller
from rest to an angular speed of 110 rad/s is
1822.5 J.
What is the moment of inertia of the pro-
peller?
Answer in units of kg · m2
3 answers
good
W_R = change in K_R = K_Rf - K_Ri = 1/2 I w^2 - 0
3000 = 1/2 I w^2 - 0
3000 = 1/2 I 200^2
I = 0.15 kg m^2
3000 = 1/2 I w^2 - 0
3000 = 1/2 I 200^2
I = 0.15 kg m^2
1 answer