assuming the density of milk is near that of water, then 1 liter of milk has 1.8 grams Lactic acid
Molarity Milk= moles/liter=1.8/90=0.02M
Molaritymilk*volumilk=molaritybase*volumebase
.02*50ml=.1*Vb
Vb=.02*50/.1=10ml about
The natural acidity of milk is 0.16% - 0.18% by mass. Predict how many mL of .1M NaOH will be required to neutralize a 50.0g sample of milk.
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