The MRT train starting at an initial velocity of 30 kph travels a distance of 21km in 18 minutes. Determine the acceleration of the train at this instant in m/s^2.

Answer 1

vf^2 = vo^2 + 2a*distance change 18 min to seconds, km to meters 30kph to m/s
and solve for a.

Answer 2

0.0865 m/s˄2