The most prominent line in the atomic spectrum of mercury occurs at a wavelength of 253.652 nm. What is the energy of 0.625 moles of photons associated with the most prominent line? Express answer in kJ.

Question

ANS:
295 kJ

Please explain.. Thank you so much!

Answer 1

E = hc/wavelength
Solve for E. Wavelength must be in m and c in m/s. E is in joules/photon; therefore, multiply by 6.02E23 to convet to a mole of photons and multiply that by 0.625 for 0.625 mols photons. The answer is in joules.

Answer 2

Got it, thank youu!