Let's break down the problem. We need to find how much water just one member of the Montanez family can use for the rest of the month. Given that the family has already used 3,485.78 gallons and they cannot exceed 7,250.50 gallons total this month, we can set up the inequality as follows:
1. Let \( x \) be the amount of water one family member can use for the remainder of the month.
2. Since each family member will use the same amount of water, the total water usage for the rest of the month would be \( 4x \).
The sum of the water already used and the additional water usage by all family members must be less than or equal to the monthly limit.
Thus, the inequality is:
\[ 4x + 3,485.78 \leq 7,250.50 \]
So, the correct choice is:
\[ 4x + 3,485.78 \leq 7,250.50 \]
The Montanez family is a family of 4 people. They have used 3,485.78 gallons of water so far this month. They cannot exceed 7,250.50 gallons per month during drought season. Write an inequality to show how much water just one member of the family can use for the remainder of the month, assuming each family member uses the same amount of water every month.
4x + 3,485.78 ≤ 7,250.50
4x − 3,485.78 ≤ 7,250.50
4x − 3,485.78 ≥ 7,250.50
4x + 3,485.78 ≥ 7,250.50
1 answer