Momentum is conserved.
0=p(gamma)+p(beta)
Answer a.
the momnetum of a gamma photon is determined by the equation p=h/lambda. for the decay of iodine-131 the relationship between the magnitude of the momentum of the gamma ray photon and the mangnitude of the momentum of the beta particle can be represented by the equation
a)p(gamma) = -p(beta)
b)p(gamma) = p(beta)
c)p(gamma) = (1.72x10^-3) x p(beta)
d)p(gamma) = (5.80x10^2) x p(beta)
[answer D]
isnt mometum conserved so should it be B? how do you come up with the foumula? thanks
1 answer
1 answer