Ma/Mb = [(Ma*Va)^2/(Mb*Vb)^2]*[Mb*Vb^2/Ma*Va^2]
= 8^2*(1/9)
= 64/9
The momentum and the kinetic energy of particle A is eight times and nine times the momentum and the kinetic energy of particle B, respectively. What is the ratio of the mass of particle A to that of particle B?
2 answers
The kinetic energy of particle A is 2 times that of particle B, and the momentum of particle A is 4 times that of B. Then, the ratio of the mass A to that of B is: