The molarity of H3PO4 is .01 M. The density of the H3PO4 in the solution is .0009 g/mL. What is the mass percent of H3PO4 in the solution, which has a density of 1.11 g/ml?

Answer 1

0.01M means 0.01 mols H3PO4/1000 mL solution. The molar mass is 98; therefore, there are 0.98 grams H3PO4/1000 mL solution.
mass solution is 1000 mL x 1.11 g/mL = 1110 grams.
mass % = (gH3PO4/g solution) = (0.98/1110)*100 = ? % w/w