The molar volume of a gas increases by a factor of 2. Which parameter change could have caused the shift in molar volume?(1 point)

Responses

the temperature increasing by a factor of 2
the temperature increasing by a factor of 2

the pressure decreasing by a factor of 0.25
the pressure decreasing by a factor of 0.25

the temperature decreasing by a factor of 0.25
the temperature decreasing by a factor of 0.25

the pressure increasing by a factor of 2

1 answer

To understand the change in molar volume of a gas, we can refer to the Ideal Gas Law, which is represented as:

\[ PV = nRT \]

Where:

  • \( P \) = pressure
  • \( V \) = volume (or molar volume)
  • \( n \) = number of moles (constant in this scenario)
  • \( R \) = ideal gas constant
  • \( T \) = temperature

Given that the molar volume increases by a factor of 2, let's analyze the options:

  1. The temperature increasing by a factor of 2: If the temperature increases while pressure remains constant, volume would increase, but not necessarily by a factor of 2.

  2. The pressure decreasing by a factor of 0.25: Lowering the pressure (by a factor of 0.25) would cause the volume to increase significantly. Mathematically, if pressure is decreased, the volume is expected to increase, possibly approaching a doubling effect, given a constant temperature.

  3. The temperature decreasing by a factor of 0.25: Decreasing the temperature while keeping pressure constant would lead to a decrease in volume, not an increase.

  4. The pressure increasing by a factor of 2: Increasing the pressure would decrease the volume, contrary to the observed increase in molar volume.

Given these considerations, the change that could have caused the shift in molar volume is:

The pressure decreasing by a factor of 0.25.