The molar solubility of gold(I) chloride is 4.510-7 mol/L. Calculate the solubility constant of this

Question

compound.

Answer 1

.......................AuCl(s) ----> Au^+ + Cl^-
I.......................solid...............0.........0
C.....................solid-x.............x..........x
E......................solid................x..........x
Ksp = (Au^+)(Cl^-) = (x)(x)
The problem tells you that x = 4.5E-7
Substitute that number and solve for Ksp.
Post your work if you get stuck.