The molar enthalpy of solution for ammonium chloride is 14.8kJ/mol. What is the final temperature observed when 20.0g of ammonium chloride is added to 125mL water at 20.0'C?

Answer 1

mols NH4Cl = 20 g/53.5 = about 0.37 but you need to do this and all other calculations here more accurately.
14.8 kJ/mol x 0.37 mol = 5.5 kJ = 5500 J.

Then -5500 J = mass H2O x specific heat H2O x (Tfinal-Tinitial)
Solve for Tf.

Answer 2

Ok thanks a lot for your help I understand it now :D

Answer 3

Can some help me with this question