The minute hand of a large clock is 0.50 m long.

(A) Calculate its linear speed at its tip in meters per second. (0.000873 m/s)
(B) Calculate the centripetal acceleration of the tip of the hand. (1.52 x 10-6 m/s2)

6 answers

it makes one trip around(2PI radians) per hour, or 3600 seconds
a. w=2PI/3600
speed=wr=2PI*.5/3600

g. a=w^2*r

(a)The angular velocity of the minute hand: w = D@/Dt = 2p/(3600 sec) = 2p/3600 = 0.001745rad/s
therefore,linear speed=wr=0.001745*0.5=0.0087rad/sec
(b)centripetal acceleration=v^2/r
=[(0.001745*0.5)^2]/0.5
=0.001745*0.001745*0.5
=0.0...3045*0.5
=given answers(1.52x10^-6)

No clue xD

Hhjiugt

Wow,

hi ira

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