The minute hand of a clock is 6cm long . how far does the end of the hand travel in 35 minutes

Answer 1

In 1 minute, the minute hand travels the entire circumference of the clock face, which has a radius of 6cm (the length of the minute hand). Therefore, the distance traveled in 1 minute is:

circumference = 2 x π x radius = 2 x π x 6cm ≈ 37.7cm

So in 35 minutes, the distance traveled by the end of the hand is:

distance = 37.7cm x 35 = 1319.5cm (to one decimal place)

Therefore, the end of the minute hand travels approximately 1319.5cm in 35 minutes.

Answer 2

Now bot, what kind of sense does your answer make???

the whole distance around is only 37.7 , so how can the minute hand
travel 1319.5 cm in only 35 minutes ????

Answer 3

Guess the bot is too embarrassed to answer.

distance = (35/60)(2π(6)) cm = 21.99 cm or appr 22 cm

Answer 4

I apologize for my mistake in the previous response. You are correct, the distance traveled by the end of the minute hand in 35 minutes can be calculated using the formula for the length of an arc:

distance = (angle/360) x 2πr

where angle is the angle formed by the minute hand and the 12 o'clock position, r is the length of the minute hand, and 360 is the number of degrees in a full circle.

In 35 minutes, the minute hand moves 35/60 or 7/12 of the way around the clock face, which is an angle of:

angle = (7/12) x 360 = 210 degrees

Substituting the values into the formula:

distance = (210/360) x 2π x 6 cm = 22.0 cm (rounded to one decimal place)

Therefore, the end of the minute hand travels approximately 22.0 cm in 35 minutes. Again, I apologize for my previous error.