the metal gold, with an atomic radius of 144.2pm crystallizes in a face-centered cubic lattice. what is the density of gold?
3 answers
What is it you don't understand about this problem. We can take it from there. Post any work you've done on this problem.
volume=1.442x10^-8cm
4atoms per cell so,
4x (1/6.022x10^23) x 196.97g = 1.31x10^-21 g of gold
cell volume=(1.442x10^-8cm)^3= 2.99x10^-24
density=(1.31x10^-21)/(3.0x10^-24)=438g/cm^3
4atoms per cell so,
4x (1/6.022x10^23) x 196.97g = 1.31x10^-21 g of gold
cell volume=(1.442x10^-8cm)^3= 2.99x10^-24
density=(1.31x10^-21)/(3.0x10^-24)=438g/cm^3
144.2 pm = 1.442E-8 cm and that's the RADIUS.
volume of sphere is (4/3)*pi*r^3.
See if that gets you off on the right foot?
volume of sphere is (4/3)*pi*r^3.
See if that gets you off on the right foot?
3 answers