Sum of heats gained is zero. Let M be the mass that is still solid.
heat added+heatmelting+heattoinceasetemp=0
300E3+(.442*900(660-100))+(.442-M)4E5=0
all are in that equation as Joules, Kg.
so solve the equation for M, the mass which is still solid at the melting point.
The melting point of aluminum is 660°C, its latent heat of fusion is 4.00 × 105 J/kg, and its specific heat is 900 J/kg • K. If 300 kJ of heat are added to 442 g of aluminum at 100°C, what is the final state of the system? That is, how much is liquid, how much is solid, and what is its temperature?
(Please write answer in essay format)
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