To compare the spread of the two datasets, we can calculate the mean absolute deviation for each dataset.
Dataset #1:
Mean = 62
Mean absolute deviation = (|51-62| + |53-62| + |56-62| + |60-62| + |72-62| + |80-62|)/6
= (11 + 9 + 6 + 2 + 10 + 18)/6
= 8.3
Dataset #2:
Mean = 62
Mean absolute deviation = (|49-62| + |55-62| + |61-62| + |63-62| + |70-62| + |74-62|)/6
= (13 + 7 + 1 + 1 + 8 + 12)/6
= 7
Dataset #2 has a smaller mean absolute deviation (7) compared to Dataset #1 (8.3). This means that Dataset #2 is less spread out compared to Dataset #1.
The mean of each dataset that follows is 62. Which dataset is less spread out? Justify your answer using the mean absolute deviation of each dataset. Round your answers to the nearest tenth.
Dataset #1: {51,53,56,60,72,80}
Dataset #2: {49,55,61,63,70,74}
(1 point)
1 answer
1 answer