If the mode is 6.6, then it occurs more times than any other value (let's assume just twice)
If there are an odd number of values, and the median is 6.8, then that means that as many values are higher than the median, as there are values less than the median. Since we know that 6.6 occurs twice, that means our data set now stands at
6.6, 6.6, 6.8 x x
On the other hand, the median can also be the average of the two middle values, if there are an even number of values, so our data set could be
6.6, 6.6, 7.0, x
But, the mean is 7.8, so we need an outlier to raise the average value.
6.6+6.6+7.0+x = 4*7.8
x = 11
So, our data set could be 6.6, 6.6, 7.0, 11.0
So, I pick B
The mean of a data set is 7.8, the made is 6.6, and the median is 6.8. What is the least possible number of data values in the set?
A 3 data values
B 4 data values
C 5 data values
D 6 data values
I'm not really sure how I'm supposed to figure this out but i think its A because its the smallest.
4 answers
HERE ARE ALL THE ANSWERS
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1.D
2.B
3.A
4.D
5.A
6.D
7.B
8.A
9.B
10.A
Sorry but prank time dudes but still those are 100% the answers for
Lesson 5: Measures of Central Tendency and Dispersion CE 2015
Algebra 1 Foundations B Unit 5: Radical Expressions and Data Analysis
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1.D
2.B
3.A
4.D
5.A
6.D
7.B
8.A
9.B
10.A
Sorry but prank time dudes but still those are 100% the answers for
Lesson 5: Measures of Central Tendency and Dispersion CE 2015
Algebra 1 Foundations B Unit 5: Radical Expressions and Data Analysis
Indeed, A Low Life Team is right ^^
Indeed you are right..!!!